Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
Equation of tangent to the parabola y2 = 16 x at P(3, 6) is
Q. Equation of tangent to the parabola
y
2
=
16
x
at
P
(
3
,
6
)
is
1675
180
MHT CET
MHT CET 2009
Report Error
A
4
x
−
3
y
+
12
=
0
B
3
y
−
4
x
−
12
=
0
C
4
x
−
3
y
−
24
=
0
D
3
y
−
x
−
24
=
0
Solution:
Equation of tangent to parabola
y
2
=
16
x
at
P
(
3
,
6
)
is
6
y
=
8
(
x
+
3
)
⇒
3
y
=
4
x
+
12
⇒
3
y
−
4
x
−
12
=
0