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  4. Equation of tangent to the parabola y2 = 16 x at P(3, 6) is

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Q. Equation of tangent to the parabola $ y^2 = 16 x $ at $ P(3, 6) $ is

MHT CETMHT CET 2009

Solution:

Equation of tangent to parabola $y^{2}=16 x$ at $P(3,6)$ is
$6 y =8(x+3) $
$\Rightarrow \,\,\,3 y =4 x+12 $
$\Rightarrow \,\,\, 3 y-4 x-12 =0$