Energy of an electron in the lowest energy state of the hydrogen atom is 13.6 eV . Find the energy needed to remove an electron from the fourth orbit.

Question

Energy of an electron in the lowest energy state of the hydrogen atom is 13.6 eV . Find the energy needed to remove an electron from the fourth orbit. (A)  13.6 eV  (B)  0.85 eV  (C)  10.2 eV  (D)  6.8 eV

Tardigrade Admin · Accepted Answer

Energy of an electron in nth state =(E1/n2) In fourth state, E4=(E1/(4)2) =(13.6/(4)2) =0.85 eV Hence, the energy reguired to remove an electron from the fourth orbit is 0.85 eV

Q. Energy of an electron in the lowest energy state of the hydrogen atom is $13.6 e V$ . Find the energy needed to remove an electron from the fourth orbit.

$13.6 e V$

$0.85 e V$

$10.2 e V$

$6.8 e V$

Energy of an electron in $n^{t h}$ state $= \frac{E _{1}}{n ^{2}}$
In fourth state, $E_{4} = \frac{E _{1}}{( 4 ) ^{2}}$
$= \frac{13.6}{( 4 ) ^{2}}$
$= 0.85 e V$
Hence, the energy reguired to remove an electron from the fourth orbit is $0.85 e V$

Q. Energy of an electron in the lowest energy state of the hydrogen atom is 13.6eV . Find the energy needed to remove an electron from the fourth orbit.

13.6eV

0.85eV

10.2eV

6.8eV