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Q.
Energy of an electron in the lowest energy state of the hydrogen atom is $ 13.6 \, eV $ . Find the energy needed to remove an electron from the
fourth orbit.
J & K CETJ & K CET 2017Atoms
Solution:
Energy of an electron in $n^{th}$ state $=\frac{E_{1}}{n^{2}}$
In fourth state, $E_{4}=\frac{E_{1}}{\left(4\right)^{2}}$
$=\frac{13.6}{\left(4\right)^{2}}$
$=0.85\,eV$
Hence, the energy reguired to remove an electron from the fourth orbit is $0.85\,eV$