Tardigrade
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Tardigrade
Question
Chemistry
Electronegativity values of elements are given K =0.8 Ge =1.8 H =2.1 Cs =0.7 P =2.1 Cl =3.0 S =2.5 F =4.0 Out of KCl , PH 3, GeCl , H 2 S and CsF ionic compounds are
Q. Electronegativity values of elements are given
K
=
0.8
G
e
=
1.8
H
=
2.1
C
s
=
0.7
P
=
2.1
Cl
=
3.0
S
=
2.5
F
=
4.0
Out of
K
Cl
,
P
H
3
,
G
e
Cl
,
H
2
S
and
C
s
F
ionic compounds are
1860
192
Chemical Bonding and Molecular Structure
Report Error
A
KCl , GeCl , CsF
23%
B
KCl, CsF
49%
C
P
H
3
,
H
2
S , KCl , CsF
19%
D
KCl , GeCl
8%
Solution:
Compound is said to be ionic if electron negativity difference between bonding atoms exceeds
1.7
.