1. Tardigrade
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  3. Chemistry
  4. Electronegativity values of elements are given K =0.8 Ge =1.8 H =2.1 Cs =0.7 P =2.1 Cl =3.0 S =2.5 F =4.0 Out of KCl , PH 3, GeCl , H 2 S and CsF ionic compounds are

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Q. Electronegativity values of elements are given
$K =0.8 \,\,\,\,\, Ge =1.8 \,\,\,\,\, H =2.1 \,\,\,\,\, Cs =0.7$
$P =2.1 \,\,\,\,\, Cl =3.0 \,\,\,\,\, S =2.5 \,\,\,\,\, F =4.0$
Out of $KCl , PH _{3}, GeCl , H _{2} S$ and $CsF$ ionic compounds are

Chemical Bonding and Molecular Structure

Solution:

Compound is said to be ionic if electron negativity difference between bonding atoms exceeds $1.7$ .