Electrode potential for Mg electrode varies according to the equation EMg2+|Mg=E°Mg2+|Mg-(0.059/2) log (1/[Mg2+]). The graph of EMg2+|Mg vs log[Mg2+] is

Question

Electrode potential for Mg electrode varies according to the equation EMg2+|Mg=E°Mg2+|Mg-(0.059/2) log (1/[Mg2+]). The graph of EMg2+|Mg vs log[Mg2+] is (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

E=E°+(0.059/2) log[Mg2+] Hence, plot of E vs [Mg2+] will be linear with positive slope and intercept = E°

Q. Electrode potential for $M g$ electrode varies according to the equation
$E_{M g^{2 +} ∣ M g} = E_{M g^{2 +} ∣ M g}^{\circ} - \frac{0.059}{2} l o g \frac{1}{[ M g ^{2 +} ]}$ .
The graph of $E_{M g^{2 +} ∣ M g} v s l o g [M g^{2 +}]$ is

$E = E^{\circ} + \frac{0.059}{2} l o g [M g^{2 +}]$
Hence, plot of $E v s [M g^{2 +}]$ will be linear with positive slope and intercept $= E^{\circ}$

Q. Electrode potential for Mg electrode varies according to the equation EMg2+∣Mg​=EMg2+∣Mg∘​−20.059​log[Mg2+]1​. The graph of EMg2+∣Mg​vslog[Mg2+] is

E=E∘+20.059​log[Mg2+] Hence, plot of Evs[Mg2+] will be linear with positive slope and intercept =E∘

Q. Electrode potential for $M g$ electrode varies according to the equation
$E_{M g^{2 +} ∣ M g} = E_{M g^{2 +} ∣ M g}^{\circ} - \frac{0.059}{2} l o g \frac{1}{[ M g ^{2 +} ]}$ .
The graph of $E_{M g^{2 +} ∣ M g} v s l o g [M g^{2 +}]$ is

$E = E^{\circ} + \frac{0.059}{2} l o g [M g^{2 +}]$
Hence, plot of $E v s [M g^{2 +}]$ will be linear with positive slope and intercept $= E^{\circ}$