Question

Electrode potential for $Mg$ electrode varies according to the equation
$E_{Mg^{2+}|Mg}=E^{\circ}_{Mg^{2+}|Mg}-\frac{0.059}{2} log \frac{1}{\left[Mg^{2+}\right]}$.
The graph of $E_{Mg^{2+}|Mg}\,vs\,log\left[Mg^{2+}\right]$ is

• A.
• B.
• C.
• D.

Answer 1

Answer: (B)

$E=E^{\circ}+\frac{0.059}{2} log\left[Mg^{2+}\right]$
Hence, plot of $ E\,vs\,\left[Mg^{2+}\right]$ will be linear with positive slope and intercept $= E^{\circ}$