E° values of some redox complexes are given below. On the basis of these values choose the correct option E° values: Br2/Br- = +1.90 V ; Ag+/Ag(s)=+1.80 V Cu2+/Cu(s)=+0.34 V; I2(s)/I-=+0.54 V

Question

E° values of some redox complexes are given below. On the basis of these values choose the correct option E° values: Br2/Br- = +1.90 V ; Ag+/Ag(s)=+1.80 V Cu2+/Cu(s)=+0.34 V; I2(s)/I-=+0.54 V (A) Cu will reduce Br- (B) Cu will reduce Ag (C) Cu will reduce I- (D) Cu will reduce Br2

Tardigrade Admin · Accepted Answer

Cu will reduce Br2 due to higher reduction potential

Q. $E^{\circ}$ values of some redox complexes are given below. On the basis of these values choose the correct option
$E^{\circ}$ values : $B r_{2} / B r^{-} = + 1.90 V; A g^{+} / A g_{(s)} = + 1.80 V$
$C u^{2 +} / C u_{(s)} = + 0.34 V; I_{2 (s)} / I^{-} = + 0.54 V$

$C u$ will reduce $B r^{-}$

$C u$ will reduce $A g$

$C u$ will reduce $I^{-}$

$C u$ will reduce $B r_{2}$

$C u$ will reduce $B r_{2}$ due to higher reduction potential

Q. E∘ values of some redox complexes are given below. On the basis of these values choose the correct option E∘ values : Br2​/Br−=+1.90V;Ag+/Ag(s)​=+1.80V Cu2+/Cu(s)​=+0.34V;I2(s)​/I−=+0.54V

Cu will reduce Br−

Cu will reduce Ag

Cu will reduce I−

Cu will reduce Br2​