Question

$E^{\circ}$ values of some redox complexes are given below. On the basis of these values choose the correct option
$E^{\circ}$ values : $Br_{2}/Br^{-} = +1.90\,V ; Ag^{+}/Ag_{(s)}=+1.80\,V$
$Cu^{2+}/Cu_{(s)}=+0.34\,V; I_{2(s)}/I^{-}=+0.54\,V$

• A. $Cu$ will reduce $Br^{-}$
• B. $Cu$ will reduce $Ag$
• C. $Cu$ will reduce $I^{-}$
• D. $Cu$ will reduce $Br_{2}$

Answer 1

Answer: (D)

$Cu$ will reduce $Br_{2}$ due to higher reduction potential