E=-(dV/dr) here negative sign sigified that

Question

E=-(dV/dr) here negative sign sigified that (A) E is opposite to V (B) E is negative (C) E increases when V decreases (D) E is directed in the direction of decreasing V

Tardigrade Admin · Accepted Answer

The negative sign is just a convention and it signifies that the direction of E is opposite to the direction in which potential increases.

Q. $E = - \frac{d V}{d r}$ here negative sign sigified that

E is opposite to V

E is negative

E increases when V decreases

E is directed in the direction of decreasing V

The negative sign is just a convention and it signifies that the direction of $E$ is opposite to the direction in which potential increases.

Q. E=−drdV​ here negative sign sigified that