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Physics
E=-(dV/dr) here negative sign sigified that
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Q. $E=-\frac{dV}{dr}$ here negative sign sigified that
Electrostatic Potential and Capacitance
A
E is opposite to V
37%
B
E is negative
15%
C
E increases when V decreases
15%
D
E is directed in the direction of decreasing V
33%
Solution:
The negative sign is just a convention and it signifies that the direction of $E$ is opposite to the direction in which potential increases.