During the qualitative analysis of SO 32 using dilute H 2 SO 4, SO 2 gas is evolved which turns K 2 Cr 2 O 7 solution (acidified with dilute H 2 SO 4 ) :

Question

During the qualitative analysis of SO 32 using dilute H 2 SO 4, SO 2 gas is evolved which turns K 2 Cr 2 O 7 solution (acidified with dilute H 2 SO 4 ) : (A) red (B) blue (C) green (D) black

Tardigrade Admin · Accepted Answer

Cr 2 O 72-+ SO 32- xrightarrow H + underset text Green Cr 3++ SO 42-

Q. During the qualitative analysis of $S O_{3}^{2}$ using dilute $H_{2} S O_{4}, S O_{2}$ gas is evolved which turns $K_{2} C r_{2} O_{7}$ solution (acidified with dilute $H_{2} S O_{4}$ ) :

red

blue

green

black

$C r_{2} O_{7}^{2 -} + S O_{3}^{2 -} H^{+} Green C r^{3 +} + S O_{4}^{2 -}$

Q. During the qualitative analysis of SO32​ using dilute H2​SO4​,SO2​ gas is evolved which turns K2​Cr2​O7​ solution (acidified with dilute H2​SO4​ ) :

red

blue

green

black

Cr2​O72−​+SO32−​H+​ Green Cr3+​+SO42−​

Q. During the qualitative analysis of $S O_{3}^{2}$ using dilute $H_{2} S O_{4}, S O_{2}$ gas is evolved which turns $K_{2} C r_{2} O_{7}$ solution (acidified with dilute $H_{2} S O_{4}$ ) :

$C r_{2} O_{7}^{2 -} + S O_{3}^{2 -} H^{+} Green C r^{3 +} + S O_{4}^{2 -}$