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Chemistry
During the qualitative analysis of SO 32 using dilute H 2 SO 4, SO 2 gas is evolved which turns K 2 Cr 2 O 7 solution (acidified with dilute H 2 SO 4 ) :
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Q. During the qualitative analysis of $SO _3^2$ using dilute $H _2 SO _4, SO _2$ gas is evolved which turns $K _2 Cr _2 O _7$ solution (acidified with dilute $H _2 SO _4$ ) :
JEE Main
JEE Main 2023
The d-and f-Block Elements
A
red
0%
B
blue
0%
C
green
100%
D
black
0%
Solution:
$Cr _2 O _7^{2-}+ SO _3^{2-} \xrightarrow{ H ^{+}} \underset{\text{ Green }}{ Cr ^{3+}}+ SO _4^{2-}$