During charging of capacitor find time when potential drop across capacitor is equal to potential drop across resistance :-

Question

During charging of capacitor find time when potential drop across capacitor is equal to potential drop across resistance :- (A) RCln3 (B) (RC ln 3/2) (C) RCln2 (D) (RC ln 2/2)

Tardigrade Admin · Accepted Answer

VR=VC V0e- t / τ=V0(1 - e- t / τ) 2e- t / τ=1 e- t / τ=(1/2) (t/τ)=ln2

Q. During charging of capacitor find time when potential drop across capacitor is equal to potential drop across resistance :-

$RCl n 3$

$\frac{RCl n 3}{2}$

$RCl n 2$

$\frac{RCl n 2}{2}$

$V_{R} = V_{C}$
$V_{0} e^{- t / τ} = V_{0} (1 - e^{- t / τ})$
$2 e^{- t / τ} = 1$
$e^{- t / τ} = \frac{1}{2}$
$\frac{t}{τ} = l n 2$

Q. During charging of capacitor find time when potential drop across capacitor is equal to potential drop across resistance :-

RCln3

2RCln3​

RCln2

2RCln2​

VR​=VC​ V0​e−t/τ=V0​(1−e−t/τ) 2e−t/τ=1 e−t/τ=21​ τt​=ln2

$RCl n 3$

$\frac{RCl n 3}{2}$

$RCl n 2$

$\frac{RCl n 2}{2}$

$V_{R} = V_{C}$
$V_{0} e^{- t / τ} = V_{0} (1 - e^{- t / τ})$
$2 e^{- t / τ} = 1$
$e^{- t / τ} = \frac{1}{2}$
$\frac{t}{τ} = l n 2$