Distance proportional to square root of time taken. The acceleration of particle proportional to

Question

Distance proportional to square root of time taken. The acceleration of particle proportional to (A) velocity (B) velocity 2 (C) velocity 3 (D) √ text velocity

Tardigrade Admin · Accepted Answer

x α √t v α t-1 / 2 a α t-3 / 2 a α(t-1 / 2)3 a α v3

Q. Distance proportional to square root of time taken. The acceleration of particle proportional to

velocity

velocity $^{2}$

velocity $^{3}$

$velocity$

$xα t$
$vα t^{- 1/2}$
$a α t^{- 3/2}$
$a α (t^{- 1/2})^{3}$
$a α v^{3}$

Q. Distance proportional to square root of time taken. The acceleration of particle proportional to

velocity

velocity 2

velocity 3

velocity ​

xαt​ vαt−1/2 aαt−3/2 aα(t−1/2)3 aαv3

velocity $^{2}$

velocity $^{3}$

$velocity$

$xα t$
$vα t^{- 1/2}$
$a α t^{- 3/2}$
$a α (t^{- 1/2})^{3}$
$a α v^{3}$