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  4. Distance proportional to square root of time taken. The acceleration of particle proportional to

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Q. Distance proportional to square root of time taken. The acceleration of particle proportional to

Motion in a Straight Line

Solution:

$x \alpha \sqrt{t}$
$v \alpha t^{-1 / 2}$
$a \alpha t^{-3 / 2}$
$a \alpha\left(t^{-1 / 2}\right)^{3}$
$a \alpha v^{3}$