Question

Distance between nodes on a string is $5cm$. Velocity of transverse wave is $2m{s}^{-1}$. Then the frequency is

• A. 5 Hz
• B. 10 Hz
• C. 20 Hz
• D. 15 Hz

Answer 1

Answer: (C)

Distance between two nodes is $\frac{\lambda }{2}$
$\therefore \frac{\lambda }{2}=5cm$ or $\lambda =10cm=0.1m$
Frequency, $v=\frac{v}{\lambda }=\frac{2}{0.1}=20Hz$