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  4. Distance between nodes on a string is 5 cm. Velocity of transverse wave is 2 m s -1. Then the frequency is

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Q. Distance between nodes on a string is $5 \,cm$. Velocity of transverse wave is $2\,m \,s ^{-1}$. Then the frequency is

Waves

Solution:

Distance between two nodes is $\frac{\lambda}{2}$
$\therefore \,\,\,\,\frac{\lambda}{2}=5\, cm \,\,\,\,$ or $\,\,\,\,\lambda=10 \,cm =0.1\, m$
Frequency, $v=\frac{v}{\lambda}=\frac{2}{0.1}=20 \,Hz$