displaystyle ∫ 010 π [(tan)- 1 x]dx=([.] = G . I . F).

Question

displaystyle ∫ 010 π [(tan)- 1 x]dx=([.] = G . I . F). (A) 10π -tan1 (B) 10-tan1 (C) 39π /4 (D) None of those

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/m-zskyjokbybmbhgfw.jpg" /> displaystyle ∫ 010 π [tan- 1 x]dx = displaystyle ∫ 0tan 10dx+ displaystyle ∫ tan 110 π 1dt =10π -tan1

Q. $\int_{0}^{10 π} [(t an)^{- 1} x] d x = ([.] = G . I . F) .$

$10 π - t an 1$

$10 - t an 1$

$39 π /4$

None of those

$\int_{0}^{10 π} [t a n^{- 1} x] d x$
$= \int_{0}^{t an 1} 0 d x + \int_{t an 1}^{10 π} 1 d t$
$= 10 π - t an 1$

Q. ∫010π​[(tan)−1x]dx=([.]=G.I.F).

10π−tan1

10−tan1

39π/4