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  4. displaystyle ∫ 010 π [(tan)- 1 x]dx=([.] = G . I . F).

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Q. $\displaystyle \int _{0}^{10 \pi }\left[\left(tan\right)^{- 1} x\right]dx=\left(\left[.\right] = G . I . F\right).$

NTA AbhyasNTA Abhyas 2022

Solution:

Solution
$\displaystyle \int _{0}^{10 \pi }\left[tan^{- 1} x\right]dx$
$=\displaystyle \int _{0}^{tan 1}0dx+\displaystyle \int _{tan 1}^{10 \pi }1dt$
$=10\pi -tan1$