Displacement-time equation of a particle moving a long x-axis is s = 8 + 3t + 4t2, then find the velocity of particle at t = 5 s.

Question

Displacement-time equation of a particle moving a long x-axis is s = 8 + 3t + 4t2, then find the velocity of particle at t = 5 s. (A) 40 m (B) 20 m (C) 43 m (D) 15 m

Tardigrade Admin · Accepted Answer

s = 8 + 3t +4t2 Differentiating with respect to t, we get (ds/dt) = 0+3 +8t at t= 5 sec (ds/dt) = v= 3+8× 5 = 43 m

Q. Displacement-time equation of a particle moving a long $x$ -axis is $s = 8 + 3 t + 4 t^{2}$ , then find the velocity of particle at $t = 5 s$ .

$40 m$

$20 m$

$43 m$

$15 m$

$s = 8 + 3 t + 4 t^{2}$
Differentiating with respect to $t$ , we get
$\frac{d s}{d t} = 0 + 3 + 8 t$
at $t = 5 sec$
$\frac{d s}{d t} = v = 3 + 8 \times 5 = 43 m$

Q. Displacement-time equation of a particle moving a long x-axis is s=8+3t+4t2, then find the velocity of particle at t=5s.

40m

20m

43m

15m