Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Physics
Displacement-time equation of a particle moving a long x-axis is s = 8 + 3t + 4t2, then find the velocity of particle at t = 5 s.
Question Error Report
Question is incomplete/wrong
Question not belongs to this Chapter
Answer is wrong
Solution is wrong
Answer & Solution is not matching
Spelling mistake
Image missing
Website not working properly
Other (not listed above)
Error description
Thank you for reporting, we will resolve it shortly
Back to Question
Thank you for reporting, we will resolve it shortly
Q. Displacement-time equation of a particle moving a long $x$-axis is $s = 8 + 3t + 4t^2$, then find the velocity of particle at $t = 5\, s$.
UP CPMT
UP CPMT 2014
Motion in a Straight Line
A
$40\,m$
10%
B
$20\,m$
13%
C
$43\,m$
69%
D
$15\,m$
8%
Solution:
$s = 8 + 3t +4t^2$
Differentiating with respect to $t$, we get
$\frac{ds}{dt} = 0+3 +8t $
at $t= 5\, sec$
$ \frac{ds}{dt} = v= 3+8\times 5 = 43\, m$