Question

Differentiate $\sin (\sin 2x).$

• A. $2\cos 2x.\cos 2x$
• B. $2\cos 2x.\cos (\sin 2x)$
• C. $2\cos 2x.\sin 2x$
• D. $\cos 2x.\cos (\sin 2x)$

Answer 1

Answer: (B)

Let $y=\sin (\sin 2x)$ Then, $\frac{dy}{dx}=\frac{d}{dx}[\sin (\sin 2x)]$
$=\cos (\sin 2x).\cos 2x.2$ $\frac{dy}{dx}=2\cos 2x.\cos (\sin 2x)$