Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. Differentiate $ \sin \,\,(\sin \,\,2x). $

J & K CETJ & K CET 2014Continuity and Differentiability

Solution:

Let $ y=\sin (\sin \,2x) $ Then, $ \frac{dy}{dx}=\frac{d}{dx}\,\,[\sin \,(\sin 2x)] $
$=\cos (\sin 2x).\cos \,2x.2 $ $ \frac{dy}{dx}=2\cos \,2x.\cos (\sin 2x) $