Q.
Determine the electrostatic potential energy of a system consisting of two charges 7μC and −2μC (and with no external field) placed at (−9cm,0,0) and (9cm,0,0), respectively
1044
139
Electrostatic Potential and Capacitance
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Solution:
The electrostatic potential energy due to system of two charges is given as U=r12Kq1q2 U=4πε01rq1q2 =9×109×0.187×(−2)×10−12=−0.7J