de-Broglie wavelength associated with an electron, accelerating through a potential difference of 100 V lies in the region of

Question

de-Broglie wavelength associated with an electron, accelerating through a potential difference of 100 V lies in the region of (A) Gamma rays (B) X-rays (C) Ultraviolet (D) Visible region

Tardigrade Admin · Accepted Answer

λ=(1.227/√V) nm =(1.227/√100)=0.123 nm which is in X-ray region.

Q. de-Broglie wavelength associated with an electron, accelerating through a potential difference of $100 V$ lies in the region of

Gamma rays

X-rays

Ultraviolet

Visible region

$λ = \frac{1.227}{V} nm = \frac{1.227}{100} = 0.123 nm$
which is in X-ray region.

Q. de-Broglie wavelength associated with an electron, accelerating through a potential difference of 100V lies in the region of