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Physics
de-Broglie wavelength associated with an electron, accelerating through a potential difference of 100 V lies in the region of
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Q. de-Broglie wavelength associated with an electron, accelerating through a potential difference of $100 \,V$ lies in the region of
Dual Nature of Radiation and Matter
A
Gamma rays
13%
B
X-rays
45%
C
Ultraviolet
29%
D
Visible region
13%
Solution:
$\lambda=\frac{1.227}{\sqrt{V}} nm =\frac{1.227}{\sqrt{100}}=0.123\, nm$
which is in X-ray region.