Cyclopropane rearranges to form propene triangle longrightarrow CH3 - CH = CH2 This follows first order kinetics. The rate constant is 2.714 × 10-3 s-1. The initial concentration of cyclopropane is 0.29 M. What will be the concentration of cyclopropane after 100 s?

Question

Cyclopropane rearranges to form propene triangle longrightarrow CH3 - CH = CH2 This follows first order kinetics. The rate constant is 2.714 × 10-3 s-1. The initial concentration of cyclopropane is 0.29 M. What will be the concentration of cyclopropane after 100 s? (A) 0.035 M (B) 0.22 M (C) 0.145 M (D) 0.0018 M

Tardigrade Admin · Accepted Answer

k = (2.303/t) log (a/(a-x)) ( a - x) is the concentration left after 100 s. 2.7 × 10-3 = (2.303/100) log (0.29/(a-x)) ⇒ (0.27/2.303) = log (0.29/(a-x)) ⇒ 0.117 = log (0.29/(a-x)) ⇒ (a-x) = 0.22 M

Q. Cyclopropane rearranges to form propene $△ ⟶ C H_{3} - C H = C H_{2}$
This follows first order kinetics. The rate constant is $2.714 \times 1 0^{- 3} s^{- 1} .$ The initial concentration of cyclopropane is $0.29 M$ . What will be the concentration of cyclopropane after $100 s$ ?

$0.035 M$

$0.22 M$

$0.145 M$

$0.0018 M$

Q. Cyclopropane rearranges to form propene △⟶CH3​−CH=CH2​ This follows first order kinetics. The rate constant is 2.714×10−3s−1. The initial concentration of cyclopropane is 0.29M. What will be the concentration of cyclopropane after 100s?

0.035M

0.22M

0.145M

0.0018M

k=t2.303​log(a−x)a​ (a−x) is the concentration left after 100s. 2.7×10−3=1002.303​log(a−x)0.29​ ⇒2.3030.27​=log(a−x)0.29​ ⇒0.117=log(a−x)0.29​ ⇒(a−x)=0.22M

Q. Cyclopropane rearranges to form propene $△ ⟶ C H_{3} - C H = C H_{2}$
This follows first order kinetics. The rate constant is $2.714 \times 1 0^{- 3} s^{- 1} .$ The initial concentration of cyclopropane is $0.29 M$ . What will be the concentration of cyclopropane after $100 s$ ?

$0.035 M$

$0.22 M$

$0.145 M$

$0.0018 M$