1. Tardigrade
  2. Question
  3. Chemistry
  4. Cyclopropane rearranges to form propene triangle longrightarrow CH3 - CH = CH2 This follows first order kinetics. The rate constant is 2.714 × 10-3 s-1. The initial concentration of cyclopropane is 0.29 M. What will be the concentration of cyclopropane after 100 s?

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Q. Cyclopropane rearranges to form propene $\triangle \longrightarrow CH_3 - CH = CH_2$
This follows first order kinetics. The rate constant is $2.714 \times 10^{-3} \, s^{-1}.$ The initial concentration of cyclopropane is $0.29\, M$. What will be the concentration of cyclopropane after $100 \,s$?

Odisha JEEOdisha JEE 2009Chemical Kinetics

Solution:

$k = \frac{2.303}{t} \, \log \, \frac{a}{(a-x)}$
$( a - x)$ is the concentration left after $100 \,s$.
$2.7 \times 10^{-3} = \frac{2.303}{100} \, \log \, \frac{0.29}{(a-x)}$
$\Rightarrow \frac{0.27}{2.303} =\log \, \frac{0.29}{(a-x)}$
$\Rightarrow 0.117 = \log \, \frac{0.29}{(a-x)}$
$\Rightarrow (a-x) = 0.22 \, M$