Current in a coil changes from 4 A to zero in 0.1 second and the emf induced is 100 V. The self inductance of the coil is

Question

Current in a coil changes from 4 A to zero in 0.1 second and the emf induced is 100 V. The self inductance of the coil is (A) 4H (B) 2.5 H (C) 0.4 H (D) 0.25 H

Tardigrade Admin · Accepted Answer

Induced emf , e =(-L d I/d t) ∴ 100 =(-L[0-4]/0.1) ⇒ L =(100 × 0.1/4) =2.5 H

Q. Current in a coil changes from $4 A$ to zero in $0.1$ second and the emf induced is $100 V$ . The self inductance of the coil is

4H

2.5 H

0.4 H

0.25 H

Induced emf , $e = \frac{- L d I}{d t}$
$∴ 100 = \frac{- L [ 0 - 4 ]}{0.1}$
$\Rightarrow L = \frac{100 \times 0.1}{4}$
$= 2.5 H$

Q. Current in a coil changes from 4A to zero in 0.1 second and the emf induced is 100V. The self inductance of the coil is

4H

2.5 H

0.4 H

0.25 H

Induced emf , e=dt−LdI​ ∴100=0.1−L[0−4]​ ⇒L=4100×0.1​ =2.5H

Q. Current in a coil changes from $4 A$ to zero in $0.1$ second and the emf induced is $100 V$ . The self inductance of the coil is

Induced emf , $e = \frac{- L d I}{d t}$
$∴ 100 = \frac{- L [ 0 - 4 ]}{0.1}$
$\Rightarrow L = \frac{100 \times 0.1}{4}$
$= 2.5 H$