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Physics
Current in a coil changes from 4 A to zero in 0.1 second and the emf induced is 100 V. The self inductance of the coil is
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Q. Current in a coil changes from $4 \,A$ to zero in $0.1$ second and the emf induced is $100\, V$. The self inductance of the coil is
KCET
KCET 2007
Electromagnetic Induction
A
4H
5%
B
2.5 H
84%
C
0.4 H
6%
D
0.25 H
5%
Solution:
Induced emf , $e =\frac{-L d I}{d t} $
$\therefore 100 =\frac{-L[0-4]}{0.1} $
$\Rightarrow L =\frac{100 \times 0.1}{4} $
$=2.5 \,H$