CsCl crystallises in body centred cubic lattice. If ‘a’ is its edge length then which of the following expressions is correct?

Question

CsCl crystallises in body centred cubic lattice. If ‘a’ is its edge length then which of the following expressions is correct? (A) rCs++ rCl-=3a (B) rCs++ rCl-=(3a/2) (C) rCs++ rCl-=(√3/2)a (D) rCs++ rCl-=√3a

Tardigrade Admin · Accepted Answer

Relation between radius of cation, anion and edge length of the cube 2 r Cs++2 r Cl- =√3 a r Cs ++ r Cl -=(√3 a/2)

Q. CsCl crystallises in body centred cubic lattice. If ‘a’ is its edge length then which of the following expressions is correct?

$r_{C s^{+}} + r_{C l^{-}} = 3 a$

$r_{C s^{+}} + r_{C l^{-}} = \frac{3 a}{2}$

$r_{C s^{+}} + r_{C l^{-}} = \frac{3}{2} a$

$r_{C s^{+}} + r_{C l^{-}} = 3 a$

Relation between radius of cation, anion and edge length of the cube
$2 r_{C s^{+}} + 2 r_{C l^{-}} = 3 a$
$r_{C s^{+}} + r_{C l^{-}} = \frac{3 a}{2}$

Q. CsCl crystallises in body centred cubic lattice. If ‘a’ is its edge length then which of the following expressions is correct?

rCs+​+rCl−​=3a

rCs+​+rCl−​=23a​

rCs+​+rCl−​=23​​a

rCs+​+rCl−​=3​a

Relation between radius of cation, anion and edge length of the cube 2rCs+​+2rCl−​=3​a rCs+​+rCl−​=23​a​

$r_{C s^{+}} + r_{C l^{-}} = 3 a$

$r_{C s^{+}} + r_{C l^{-}} = \frac{3 a}{2}$

$r_{C s^{+}} + r_{C l^{-}} = \frac{3}{2} a$

$r_{C s^{+}} + r_{C l^{-}} = 3 a$

Relation between radius of cation, anion and edge length of the cube
$2 r_{C s^{+}} + 2 r_{C l^{-}} = 3 a$
$r_{C s^{+}} + r_{C l^{-}} = \frac{3 a}{2}$