Question

Critical angle for certain medium is $Sin ^{-1}$ $(0.6)$. The polarizing angle of that medium is .......

• A. $Tan ^{-1} [1.6667]$
• B. $Tan ^{-1} [0.6667]$
• C. $Tan ^{-1} [1.5]$
• D. $Sin ^{-1} [0.8]$

Answer 1

Answer: (A)

Critical angle, $C=\sin ^{-1}(0.6)$
$\sin (C)= 0.6$
$\mu= \frac{1}{\sin C}=\frac{1}{0.6}$
Polarising angle $i_{p}=\tan ^{-1}(\mu)=\tan ^{-1}\left(\frac{1}{0.6}\right)$
$=\tan ^{-1}(1.6667)$