Question

$C{r}^{2+}$ and $M{n}^{3+}$ both have $d^4$ configuration. Thus

• A. Both are reducing agents
• B. Both are oxidizing agents
• C. $C{r}^{2+}$ is oxidizing agent while $M{n}^{3+}$ is reducing agent
• D. $M{n}^{3+}$ is oxidizing agent while $C{r}^{2+}$ is reducing agent

Answer 1

Answer: (D)

$C{r}^{2+}$ is reducing agent because $C{r}^{2+}$ donate electron to attain stable $d^3{t}_{2g}$ half filled and configuration, where as $M{n}^{3+}$ accept electron due to strong reduction potential to form $d^5$ stable $M{n}^{2+}$. So, $C{r}^{2+}$ is reducing $M{n}^{3+}$ is oxidizing agent.