Question

$Cr ^{2+}$ and $Mn ^{3+}$ both have $d^{4}$ configuration. Thus

• A. Both are reducing agents
• B. Both are oxidizing agents
• C. $C r^{2+}$ is oxidizing agent while $M n^{3+}$ is reducing agent
• D. $M n^{3+}$ is oxidizing agent while $C r^{2+}$ is reducing agent

Answer 1

Answer: (D)

$Cr ^{2+}$ is reducing agent because $Cr ^{2+}$ donate electron to attain stable $d^{3} t_{2 g}$ half filled and configuration, where as $M n^{3+}$ accept electron due to strong reduction potential to form $d^{5}$ stable $M n^{2+}$. So, $C r^{2+}$ is reducing $M n^{3+}$ is oxidizing agent.