Correct order of stability of hydrides of carbon family is

Question

Correct order of stability of hydrides of carbon family is (A) CH4 > SiH4 > GeH4> SnH4> PbH4 (B) CH4 < SiH4 < GeH4 < SnH4 < PbH4 (C) CH4 > SnH4 > GeH4 > SnH4> PbH4 (D) None of the above

Tardigrade Admin · Accepted Answer

Hydride of carbon family is stable when carbon is near to nucleus, thus its attraction is more toward valence shell electron so, it is more stable CH4> SiH4> GeH4 > SnH4> PbH4

Q. Correct order of stability of hydrides of carbon family is

$C H_{4} > S i H_{4} > G e H_{4} > S n H_{4} > P b H_{4}$

$C H_{4} < S i H_{4} < G e H_{4} < S n H_{4} < P b H_{4}$

$C H_{4} > S n H_{4} > G e H_{4} > S n H_{4} > P b H_{4}$

None of the above

Hydride of carbon family is stable when carbon is near to nucleus, thus its attraction is more toward valence shell electron so, it is more stable
$C H_{4} > S i H_{4} > G e H_{4} > S n H_{4} > P b H_{4}$

Q. Correct order of stability of hydrides of carbon family is

CH4​>SiH4​>GeH4​>SnH4​>PbH4​

CH4​<SiH4​<GeH4​<SnH4​<PbH4​

CH4​>SnH4​>GeH4​>SnH4​>PbH4​

None of the above

Hydride of carbon family is stable when carbon is near to nucleus, thus its attraction is more toward valence shell electron so, it is more stable CH4​>SiH4​>GeH4​>SnH4​>PbH4​

$C H_{4} > S i H_{4} > G e H_{4} > S n H_{4} > P b H_{4}$

$C H_{4} < S i H_{4} < G e H_{4} < S n H_{4} < P b H_{4}$

$C H_{4} > S n H_{4} > G e H_{4} > S n H_{4} > P b H_{4}$

Hydride of carbon family is stable when carbon is near to nucleus, thus its attraction is more toward valence shell electron so, it is more stable
$C H_{4} > S i H_{4} > G e H_{4} > S n H_{4} > P b H_{4}$