Question

Correct order of stability of hydrides of carbon family is

• A. $CH_{4} >\,SiH_{4} >\, GeH_{4}>\, SnH_{4}>\, PbH_{4}$
• B. $CH_{4} <\, SiH_{4} <\,GeH_{4} <\,SnH_{4} <\,PbH_{4}$
• C. $CH_{4} >\,SnH_{4} >\,GeH_{4} >\, SnH_{4}>\, PbH_{4}$
• D. None of the above

Answer 1

Answer: (A)

Hydride of carbon family is stable when carbon is near to nucleus, thus its attraction is more toward valence shell electron so, it is more stable
$CH_{4}>\, SiH_{4}>\, GeH_{4} >\, SnH_{4}>\,PbH_{4}$