Correct order of bond angles for the following is

Question

Correct order of bond angles for the following is (A) NH3 > PCl3 > BCl3 (B) BCl3 > NH3 > PCl3 (C) BCl3 > PCl3 > NH3 (D) PCl3 > BCl3 >NH3

Tardigrade Admin · Accepted Answer

BCI3 is trigonal in shape where bond angle is 120°. In NH3 and PCI3 (both are having pyramidal geometry), though the central atom has equal number of Ione pairs and bond pairs, the valence shell of P is relatively bigger and pond angle is Iower.

Q. Correct order of bond angles for the following is

$N H_{3} > PC l_{3} > BC l_{3}$

$BC l_{3} > N H_{3} > PC l_{3}$

$BC l_{3} > PC l_{3} > N H_{3}$

$PC l_{3} > BC l_{3} > N H_{3}$

BCI $_{3}$ is trigonal in shape where bond angle is 120 $^{\circ}$ . In NH $_{3}$ and PCI $_{3}$ (both are having pyramidal geometry), though the central atom has equal number of Ione pairs \and bond pairs, the valence shell of P is relatively bigger and pond angle is Iower.

Q. Correct order of bond angles for the following is

NH3​>PCl3​>BCl3​

BCl3​>NH3​>PCl3​

BCl3​>PCl3​>NH3​

PCl3​>BCl3​>NH3​

BCI3​ is trigonal in shape where bond angle is 120∘. In NH3​ and PCI3​ (both are having pyramidal geometry), though the central atom has equal number of Ione pairs \and bond pairs, the valence shell of P is relatively bigger and pond angle is Iower.

$N H_{3} > PC l_{3} > BC l_{3}$

$BC l_{3} > N H_{3} > PC l_{3}$

$BC l_{3} > PC l_{3} > N H_{3}$

$PC l_{3} > BC l_{3} > N H_{3}$

BCI $_{3}$ is trigonal in shape where bond angle is 120 $^{\circ}$ . In NH $_{3}$ and PCI $_{3}$ (both are having pyramidal geometry), though the central atom has equal number of Ione pairs \and bond pairs, the valence shell of P is relatively bigger and pond angle is Iower.