Copper sulphate solution is electrolysed between two platinum electrodes. A current is passed until 1.6g of oxygen is liberated at anode. The amount of copper deposited at the cathode during the same period is: [At. mass of Cu=63.6].

Question

Copper sulphate solution is electrolysed between two platinum electrodes. A current is passed until 1.6g of oxygen is liberated at anode. The amount of copper deposited at the cathode during the same period is: [At. mass of Cu=63.6]. (A) 6.36g (B) 63.6g (C) 12.7g (D) 3.2g

Tardigrade Admin · Accepted Answer

For O2,m=(E × Q/nF) and Q=(m/E)× nF=0.2F For Cu,m=(E × Q/nF)=(63 .5/2 × F)× 0.2F=6.36g Hence, (.1.) is correct.

Q. Copper sulphate solution is electrolysed between two platinum electrodes. A current is passed until $1.6 g$ of oxygen is liberated at anode. The amount of copper deposited at the cathode during the same period is: [At. mass of $C u = 63.6]$

$6.36 g$

$63.6 g$

$12.7 g$

$3.2 g$

For $O_{2}, m = \frac{E \times Q}{n F}$ and $Q = \frac{m}{E} \times n F = 0.2 F$
For $C u, m = \frac{E \times Q}{n F} = \frac{63.5}{2 \times F} \times 0.2 F = 6.36 g$
Hence, $(1)$ is correct.

Q. Copper sulphate solution is electrolysed between two platinum electrodes. A current is passed until 1.6g of oxygen is liberated at anode. The amount of copper deposited at the cathode during the same period is: [At. mass of Cu=63.6]

6.36g

63.6g

12.7g

3.2g