Considering the following reaction, find the equivalent weight of chlorine, given that molar mass of Cl2 is M. Cl2+NaOH overset arrow NaCl+NaClO3+H2O

Question

Considering the following reaction, find the equivalent weight of chlorine, given that molar mass of Cl2 is M. Cl2+NaOH overset arrow NaCl+NaClO3+H2O (A) (5/3)M (B) (3/5)M (C) (M/3) (D) (2/3)M

Tardigrade Admin · Accepted Answer

Considering half oxidation and half reduction reaction:
Oxidation:

6 O H + \frac{1}{2} C l_{2} \to 2 Cl O_{3} + 3 H_{2} O + 5 e^{-}

Reduction:

\frac{5}{2} C l_{2} + 5 e^{-} \to 5 C l^{-}

3 moles of

C l_{2}

and 5 moles of electrons are involved in the redox reaction

e q u i v a l e n t ma ss = \frac{m o l ec u l a r ma ss}{n f a c t or} = \frac{3}{5} M

Q. Considering the following reaction, find the equivalent weight of chlorine, given that molar mass of $C l_{2}$ is M.
$C l_{2} + N a O H \to N a Cl + N a Cl O_{3} + H_{2} O$

$\frac{5}{3} M$

$\frac{3}{5} M$

$\frac{M}{3}$

$\frac{2}{3} M$

Q. Considering the following reaction, find the equivalent weight of chlorine, given that molar mass of Cl2​ is M. Cl2​+NaOH→NaCl+NaClO3​+H2​O

35​M

53​M

3M​

32​M

Considering half oxidation and half reduction reaction: Oxidation: 6OH+21​Cl2​→2ClO3​+3H2​O+5e− Reduction: 25​Cl2​+5e−→5Cl− 3 moles of Cl2​ and 5 moles of electrons are involved in the redox reaction equivalentmass=nfactormolecularmass​=53​M

Q. Considering the following reaction, find the equivalent weight of chlorine, given that molar mass of $C l_{2}$ is M.
$C l_{2} + N a O H \to N a Cl + N a Cl O_{3} + H_{2} O$

$\frac{5}{3} M$

$\frac{3}{5} M$

$\frac{M}{3}$

$\frac{2}{3} M$