Consider two solid spheres of radii R1=1m , R2=2m and masses M1 and M2, respectively. The gravitational field due to sphere (1) and (2) are shown. The value of (M1/M2) is:

Question

Consider two solid spheres of radii R1=1m , R2=2m and masses M1 and M2, respectively. The gravitational field due to sphere (1) and (2) are shown. The value of (M1/M2) is: <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-beuieuxpdohohjkp.jpg" /> (A) (2/3) (B) (1/6) (C) (1/2) (D) (1/3)

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/p-beuieuxpdohouxza.jpg" /> 3=(G M2/22) 2=(G M1/12) ∴ (3/2)=(1/4)(M2/M1) (M1/M2)=(1/6)

Q. Consider two solid spheres of radii $R_{1} = 1 m$ , $R_{2} = 2 m$ and masses $M_{1}$ and $M_{2},$ respectively. The gravitational field due to sphere $(1)$ and $(2)$ are shown. The value of $\frac{M _{1}}{M _{2}}$ is:

$\frac{2}{3}$

$\frac{1}{6}$

$\frac{1}{2}$

$\frac{1}{3}$

$3 = \frac{G M _{2}}{2 ^{2}}$
$2 = \frac{G M _{1}}{1 ^{2}}$
$∴ \frac{3}{2} = \frac{1}{4} \frac{M _{2}}{M _{1}}$
$\frac{M _{1}}{M _{2}} = \frac{1}{6}$

Q. Consider two solid spheres of radii R1​=1m , R2​=2m and masses M1​ and M2​, respectively. The gravitational field due to sphere (1) and (2) are shown. The value of M2​M1​​ is:

32​

61​

21​

31​