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  4. Consider two solid spheres of radii R1=1m , R2=2m and masses M1 and M2, respectively. The gravitational field due to sphere (1) and (2) are shown. The value of (M1/M2) is: <img class=img-fluid question-image alt=Question src=https://cdn.tardigrade.in/q/nta/p-beuieuxpdohohjkp.jpg />

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Q. Consider two solid spheres of radii $R_{1}=1m$ , $R_{2}=2m$ and masses $M_{1}$ and $M_{2},$ respectively. The gravitational field due to sphere $\left(1\right)$ and $\left(2\right)$ are shown. The value of $\frac{M_{1}}{M_{2}}$ is:
Question

NTA AbhyasNTA Abhyas 2022

Solution:

Solution
$3=\frac{G M_{2}}{2^{2}}$
$2=\frac{G M_{1}}{1^{2}}$
$\therefore \frac{3}{2}=\frac{1}{4}\frac{M_{2}}{M_{1}}$
$\frac{M_{1}}{M_{2}}=\frac{1}{6}$