Question

Consider the vernier callipers shown below. The instrument has no zero error. If $1m.s.d=1mm$ and $7m.s.d=8v.s.d$ , then what is the length (in $mm$ ) of the rod shown in the figure? [Given; the $4^{th}v.s.d$ coincides with $m.s.d$ ]

Answer 1

Answer: 4.5

$7m.s.d=8v.s.d$
$\Rightarrow 1v.s.d=\frac{7}{8}m.s.d$
$\Rightarrow L.C=\left(1-\frac{7}{8}\right)mm=\frac{1}{8}mm$
Were $M.S.R=4mm$
$V.S.R=4$
value $=\left(4+(4)\left(\frac{1}{8}\right)\right)mm$
$=4.5mm$