Consider the system as shown in the figure. The pulley and the string are light and all the surfaces are frictionless. The tension in the string is (g = 10 m/s2)

Question

Consider the system as shown in the figure. The pulley and the string are light and all the surfaces are frictionless. The tension in the string is (g = 10 m/s2) <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/ebb773e8ba811b9ff0e512b5b467e233-.png" /> (A) 0 N (B) 1 N (C) 2 N (D) 5 N

Tardigrade Admin · Accepted Answer

The acceleration of block of mass m1 is

a=(m1/m1+m2) g=5 m/s2 From FBD of block m1

m1g-T=m1a ⇒ T=m1(g-a) =1 × 5 =5 N

Q. Consider the system as shown in the figure. The pulley and the string are light and all the surfaces are frictionless. The tension in the string is $(g = 10 m / s^{2})$

$0 N$

$1 N$

$2 N$

$5 N$

The acceleration of block of mass $m_{1}$ is

$a = \frac{m _{1}}{m _{1} + m _{2}}$

$g = 5 m / s^{2}$

From FBD of block $m_{1}$

$m_{1} g - T = m_{1} a$

$\Rightarrow T = m_{1} (g - a)$

$= 1 \times 5 = 5 N$

Q. Consider the system as shown in the figure. The pulley and the string are light and all the surfaces are frictionless. The tension in the string is (g=10m/s2)

0N

1N

2N

5N