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  4. Consider the system as shown in the figure. The pulley and the string are light and all the surfaces are frictionless. The tension in the string is (g = 10 m/s2) <img class=img-fluid question-image alt=image src=https://cdn.tardigrade.in/img/question/physics/ebb773e8ba811b9ff0e512b5b467e233-.png />

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Q. Consider the system as shown in the figure. The pulley and the string are light and all the surfaces are frictionless. The tension in the string is $(g = 10\, m/s^{2})$
image

Laws of Motion

Solution:

The acceleration of block of mass $m_{1}$ is
image
$a=\frac{m_{1}}{m_{1}+m_{2}}$
$g=5\,m/s^{2}$
From FBD of block $m_{1}$
image
$m_{1}g-T=m_{1}a$
$\Rightarrow T=m_{1}(g-a)$
$=1 \times 5 =5\,N$