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Q. Consider the situation shown in the figure. The wall is smooth but the surfaces of blocks $A$ and $B$ in contact are rough. The friction on $A$ due to $B$ in equilibrium



Question

NTA AbhyasNTA Abhyas 2020Laws of Motion

Solution:

Solution

Block 'A' cannot be in equilibrium. Due to F sin θ component (upwards) on block 'B', Block 'A' moves downwards relative to block 'B'. So, friction on block 'B' downwords.