Consider the reaction: (T = 298 K) Cl2(g) + 2Br-(aq) → 2Cl- (aq) + Br2 (aq.) The emf of the cell, when [Cl-] = [Br2] = [Br] = 0.01M and Cl2 gas is at 1 atm pressure, will be: (Eo for the above reaction is= 0.29 volt)

Question

Consider the reaction: (T = 298 K) Cl2(g) + 2Br-(aq) → 2Cl- (aq) + Br2 (aq.) The emf of the cell, when [Cl-] = [Br2] = [Br] = 0.01M and Cl2 gas is at 1 atm pressure, will be: (Eo for the above reaction is= 0.29 volt) (A) 0.54 volt (B) 0.35 volt (C) 0.24 volt (D) -0.29 volt

Tardigrade Admin · Accepted Answer

Ecell=0.29 -(0.059/2)log (0.01×(0.01)2/(0.01)2×1) or Ecell =0.35 volt

Q. Consider the reaction: (T = 298 K)
$C l_{2} (g) + 2 B r^{-} (a q) \to 2 C l^{-} (a q) + B r_{2} (a q .)$
The emf of the cell, when $[C l^{-}] = [B r_{2}] = [B r] = 0.01 M$ and $C l_{2}$ gas is at 1 atm pressure, will be: ( $E^{o}$ for the above reaction is $= 0.29$ volt)

$0.54$ volt

$0.35$ volt

$0.24$ volt

$- 0.29$ volt

$E_{ce ll} = 0.29 - \frac{0.059}{2} l o g \frac{0.01 \times ( 0.01 ) ^{2}}{( 0.01 ) ^{2} \times 1}$
or $E_{ce ll} = 0.35 v o lt$

Q. Consider the reaction: (T = 298 K) Cl2​(g)+2Br−(aq)→2Cl−(aq)+Br2​(aq.) The emf of the cell, when [Cl−]=[Br2​]=[Br]=0.01M and Cl2​ gas is at 1 atm pressure, will be: (Eo for the above reaction is=0.29 volt)

0.54 volt

0.35 volt

0.24 volt

−0.29 volt