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Q. Consider the reaction: (T = 298 K)
$Cl_{2}(g) + 2Br^{-}(aq) \to 2Cl^{-} (aq) + Br_{2} (aq.)$
The emf of the cell, when $[Cl^{-}] = [Br_{2}] = [Br] = 0.01M$ and $Cl_{2}$ gas is at 1 atm pressure, will be: ($E^{o}$ for the above reaction is$= 0.29$ volt)

Electrochemistry

Solution:

$E_{cell}=0.29 -\frac{0.059}{2}log \frac{0.01\times\left(0.01\right)^{2}}{\left(0.01\right)^{2}\times1} $
or $E_{cell} =0.35 \,volt$