Consider the reaction sequence from P to Q shown below. The overall yield of the major product Q from P is 75 %. What is the amount in grams of Q obtained from 9.3 mL of P ? (Use density of P =1.00 g mL -1; Molar mass of C =12.0, H =1.0, O =16.0 and N =14.0 g mol -1 )

Question

Consider the reaction sequence from P to Q shown below. The overall yield of the major product Q from P is 75 %. What is the amount in grams of Q obtained from 9.3 mL of P ? (Use density of P =1.00 g mL -1; Molar mass of C =12.0, H =1.0, O =16.0 and N =14.0 g mol -1 ) (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/4c02eab77fd9c602d014db581fb2341d-.png" /> Moles of P=(9.3/93)=0.1= moles of Q. So, mass of (Q)=0.1 × 248 × 0.75=18.60 gram

Q. Consider the reaction sequence from P to Q shown below. The overall yield of the major product Q from P is 75%. What is the amount in grams of Q obtained from 9.3mL of P? (Use density of P=1.00gmL−1; Molar mass of C=12.0,H=1.0,O=16.0 and N=14.0gmol−1 )

Moles of P=939.3​=0.1= moles of Q. So, mass of (Q)=0.1×248×0.75=18.60 gram

Moles of $P = \frac{9.3}{93} = 0.1 =$ moles of $Q$ .
So, mass of $(Q) = 0.1 \times 248 \times 0.75 = 18.60$ gram